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Bab Fungsi Komposisi
Matematika SMA Kelas X

(hofog) (x) = (hof) (x + 5)
(hofog) (x) = h (4 (x + 5) - 3)
(hofog) (p) = (4p + 17)² - 7(4p + 17) + 4 = -6
16p² + 136p + 289 - 28p - 119 + 4 + 6 = 0
16p² + 108p + 170 = 0
 8p² + 54p + 85 = 0
(4p + 17) (2p + 5) = 0
4p + 17 = 0 atau 2p + 5 = 0
4p = -17              2p = -5
p = -17/4               p = -5/2