bagaimana cara detailnya ?mohon bantuannya

Turunan dan integral

1a)
f'(x)= 6x + 2 , f(-2)= 5
f(x) = ∫ f '(x) dx
f(x)= ∫ 6x +2 dx
f(x)= 3x² + 2x + c
f(-2)= 5
3(2²)+ 2(2) + c = 5
12 + 4 + c = 5
c = 5-16
c = -11
f(x)= 3x² + 2x - 11

2a)
dy/dx = 3x² + 2  melalui (2, -1)
f (x)= ∫ 3x² +2 dx
f(x)= x³ + 2x + c melalui (2,1)
1 = 2³+ 2(2) + c
1= 8 + 4 + c
c = -11
f(x)= 3x² +2x - 11

3.
f " (x)= 6x - 4

a.)
f '(x)= ∫6x -4 dx = 3x² - 4x + c
f'(2)= 5 --> 3(2²) - 4(2) + c = 5
12-8 + c = 5
4 +c = 5
c = 1
f'(x)= 3x² - 4x + 5

b) f(x)= ∫ f' (x) dx

f(x)= ∫ 3x² - 4x + 5 dx
f(x)= x³ - 2x² + 5x + c
f(-2)= 3
2³ - 2.2² + 5.2 + c = 3
8 - 8 + 10 + c = 3
c= -7
f(x) = x³ - 2x² + 5x - 7