Matematika

Pertanyaan

Tentukan nilai n yang memenuhi : 6nC2=(n+2)C4

2 Jawaban

  • 6nC2=(n+2)C4
    6nC2= nC4+8
    6-8= nC4/nC2
    -2= 2n
    -1 = n
  • 6 . nC2 = (n + 2)C4
    6 . n!/(n - 2)!2! = (n + 2)!/(n + 2 - 4)!4!
    6 . n(n - 1)(n - 2)!/(n - 2)!.2.1 = (n + 2)(n + 1)(n)(n - 1)(n - 2)!/(n - 2)!4.3.2.1
    6 . n(n - 1) / 2 = (n + 2)(n + 1)n(n - 1)/24
    6 / 2 = (n + 2)(n + 1)/24
    3 = (n^2 + 3n + 2)/24
    3(24) = n^2 + 3n + 2
    n^2 + 3n + 2 - 72 = 0
    n^2 + 3n - 70 = 0
    (n + 10)(n - 7) = 0
    n = -10 atau n = 7
    Yang kita ambil n = 7 => harus bilangan asli

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