tolong jawab ya... selesaikanlah sistim persamaan berikut dgn metode subtitusi! 4x + 1y = 10 6x - 3y = 6

4x+y=10 ===>y=10-4x
6x-3y=6 
                    
6x-3y=6
6x-3(10-4x)=6
6x-(30-12x)=6
6x-30+12x=6
18x=36
x=2

6x-3y=6
6(2)-3y=6
12-3y=6
-3y=6-12
-3y=-6
y=2

HP={2,2}  

4x + 1y = 10 ---->> y = 10 - 4x ............. (1)
6x - 3y = 6 ........... (2)

Subtitusikan 1 ke 2 ↓↓↓
6x - 3y = 6
6x - 3(10 - 4x) = 6
6x - 30 + 12x = 6
6x + 12x = 6 + 30
18x = 36
x = 36/18
x = 2

Subtitusikan "x" ke 1 ↓↓↓
y = 10 - 4x
y = 10 - 4(2)
y = 10 - 8
y = 2

Maka, x = 2 dan y = 2