jika f(x)=x⁴-x³+2x²-1, maka f'(1) adalah

Bab Turunan

f'(x) = 4.x^(4 - 1) - 3.x^(3 - 1) + 2.2x^(2 - 1) - 0.1x^(0 - 1)
f'(x) = 4x^3 - 3x^2 + 4x
f'(1) = 4(1)^3 - 3(1)^2 + 4(1)
f'(1) = 4 - 3 + 4
f'(1) = 5

Cari f'(x) dlu

Jika f(x) = ax^n
Maka f'(x) = an . x^(n-1)

f(x) = x^4 - x^3 + 2x^2 - 1(x^0)
f'(x) = 4x^3 - 3x^2 + 4x

f'(1) = 4 . (1)^3 - 3 . (1)^2 + 4 . 1
f'(1) = 4 - 3 + 4
f'(1) = 5

Ingat 1 dipangkatin brp aja hasilnya ttp 1.