TITIK A(4,210˚), B(8,150˚), JARAK AB ADALAH..........

A(4,210°)
x = 4 cos 210
x = 4 * -1/2 akar 3
x = -2akar3

y = 4sin 210
y = 4 * -1/2
y = -2
A(-2akar3, -2)

B(8,150°)
x = 8 cos 150
x = 8 * -1/2akar 3
x = -4akar3

y = 8 sin 150
y = 8*1/2
y = 4
B(-4akar3, 4)

jarak AB
= B - A
= (-4akar3,4) - (-2akar3,-2)
= (-2akar3, 6)