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Pertanyaan

100 ml larutan (CH3COO)2 Ca 0,1 M memiliki harga pH...(Ka CH3COOH= 10^-5)
a. 5
b. 9 + log 1
c. 5 - log 1,4
d. 9 + log 1,4
e. 12

1 Jawaban

  • OH- = akar Kw/Ka [G]n
    = akar 10^-14/10^-5 [2 x 0,1]
    = akar 2.10^-10
    = 1,4.10^-5 M

    pOH = 5 - log 1,4
    pH = 9 + log 1,4

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