nilai cos 30° + sin² 45° + tan 60°/ sec 60° tan 45°
Matematika
silviana41
Pertanyaan
nilai cos 30° + sin² 45° + tan 60°/ sec 60° tan 45°
2 Jawaban
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1. Jawaban danieldaniswara
[tex] \frac{cos30+sin45+tan60}{sec60.tan45} [/tex]
= [tex] \frac{1}{2} [/tex]√3 + [tex] \frac{1}{2} [/tex]√2 +√3 / 2 · 1
= [tex] \frac{1}{4} [/tex]√3 + [tex] \frac{1}{4} [/tex]√2 + [tex] \frac{1}{2} [/tex]√3
semoga membantu -
2. Jawaban Ashiela
cos 30 = ½√3
sin 45 = ½√2
tan 60 = √3
sec 60 = 1 / cos 60 = 1 / ½ = 2
tan 45 = 1
(cos 30° + sin² 45° + tan 60°) / sec 60° tan 45°
= (½√3 + (½√2)² + √3) / 2 × 1
= (3/2 √3 + 1) / 2
= ¾√3 + ½
=