Diketahui f(x)=x²+3x-2,g(x)=x+3,dan f(x)= 2x + 1. nilai (f=g=h)(3)

f(x) = x²+3x-2
g(x) = x+3
h(x) = 2x+1

(f•g•h)(3)
= f(g(h(3)))
= f(g(2.3+1))
= f(g(7))
= f(7+3)
= f(10)
= (10²) + 3(10) - 2
= 100 + 30 - 2
= 128