integral dari x(x+4)^5 dx mohon bantuannya

Integral Fungsi Aljabar.
Kelas XI kurikulum 2013 revisi 2016.

Integral substitusi.
∫ x (x + 4)⁵ dx
u = x + 4 → x = u - 4
du / dx = 1 → dx = du 
= ∫ (u - 4) u⁵ du
= ∫ (u⁶ - 4u⁵) du
= 1/7 u⁷ - 2/3 u⁶ + C
= 1/7 (x + 4)⁷ - 2/3 (x + 4)⁶ + C
= 1/21 [3(x + 4)⁶(x + 4) - 14(x + 4)⁶] + C
= 1/21 {(x + 4)⁶ [3(x + 4) - 14]} + C
= 1/21 [(x + 4)⁶(3x - 2)] + C