mohon bantuannya dengan cara terimakasih

r = √-12² + -12² = = √288 = 12√2
teta = tan^-1 -12/-12 = 225°
koordinat kutub (12√2,225°)

A(-12, -12) => dikuadran 3
r = √(x^2 + y^2) = √(-12^2 + -12^2) = √(144 + 144) = √288 = 12√2
Tan a = y/x = -12/-12 = 1 => Tan (180° + 45°) => Tan 225°
a = 225°
Koordinat kutub = (r, a) = (12√2, 225°)