Tolong d jaawab 24 sin 75 derajat cos 15derajat

24 sin 75° cos 15° (?)

= 24 sin (45° + 30°) cos (45° - 30°)

= 24 [sin 45°.cos 30° + cos 45°.cos 30°] [cos45°.cos30° + sin45°.sin 30°]

=24 [(1/2 √2) * (1/2) + (1/2 √2) * (1/2 √3)] [(1/2 √2) * (1/2 √3) + (1/2 √2) * (1/2)]

= 24 [ (1/4 √2) + (1/4 √6) ] [ (1/4 √6) + (1/4 √2) ]

= 24 [ (1/4 √2) + (1/4 √6) ]^2

= 24 [ (1/4 √2)^2 + 2*(1/4 √2)*(1/4 √6) + (1/4 √6)^2 ]

= 24 [ (1/16 * 2) + (1/8 * √12) + (1/16 * 6)

= 24 [ 1/8 + (1/8 * √4*√3) + 3/8 ]

= 24 [ 1/8 + (2/8 * √3) + 3/8 ]

= 3 + 6√3 + 9

= 6√3 + 12