Tolong di jawab kakak.. Diketahui fungsi f(x)=3x²,g(x)=2x+4 dan h(x)=5-x hasil (hogof)(x) adalah

(hogof)(x)
= h(g(f(x)))
= h(g(3x^2))
= h(2(3x^2)+4)
= h(6x^2 + 4)
=5 - (6x^2 + 4)
= 1 - 6x^2
atau
= -6x^2 +1

^ dibaca pangkat

(g o f)(x) = g(f(x)) = g(3x^2) = 2(3x^2) + 4 = 6x^2 + 4

(h o g o f)(x) = (h o (g o f))(x)
= h((g o f)(x))
= h(6x^2 + 4)
= 5 - (6x^2 + 4)
= 5 - 6x^2 - 4
= 1 - 6x^2