nilai dari 30°12'=....rad
Matematika
rinafitriana21
Pertanyaan
nilai dari 30°12'=....rad
1 Jawaban
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1. Jawaban danieldaniswara
30°12' = 30° + [tex] \frac{12}{60} [/tex]° = 30° + 0,2° = 30,2°
=30,2° × π/180
=30,2π / 180
= 0,167π rad