tolong dibantuu soal mtk turunan

f(x) = (x²+3) /(2x+1)
f'(x)= [2x(2x+1) - 2(x²+3)] / (2x+1)²
f' (x) = [ 4x² +2x - 2x² - 6 ] / [2x +1]²

f '(0) = (-6)/ (1) = - 6
f(0)= 3/1 = 3
 
f(0) + 2 f '(0) = 3 + 2(-6) = 3 - 12 = -9

maaf kalo salah.

good luck
:-)
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