luas segitiga ABC adalah....

misal garis yg tegak lurus antara AC = O

OB/sin C = OC/sin B
3/sin 60 = OC/sin 30
OC = 3 sin 30/sin 60
OC = akar 3

maka
AC = 1 + akar 3

luas segitiga
= 1/2 * AC * OC
= 1/2 * (1 + akar 3) * 3
= 3/2 + (3 akar 3)/2 cm²

jawaban E