Kimia

Pertanyaan

help no. 22 sampe 28 dengan cara.
thx banget yang bantu, semoga sehat, rezeki lancar aamiiin
help no. 22 sampe 28 dengan cara. thx banget yang bantu, semoga sehat, rezeki lancar aamiiin

1 Jawaban

  • 22. Mg₃(PO₄)₂ (B) ⇒ Jawab
    23. C₄H₁₀ (g) + ¹³/₂O₂ (g) ⇒ 4CO₂ (g) + 5H₂O (g)
    atau
    Reaksi dikali 2 :
    2C₄H₁₀ (g) + 13O₂ (g) ⇒ 8CO₂ (g) + 10H₂O (g)
    2, 13, 8, dan 10 (B) ⇒ Jawab
    24. Avogadro (D) ⇒ Jawab
    25. JP CO₂ = n CO₂ x L
    6.02 . 10²² = n CO₂ x 6.02 . 10²³
    n CO₂ = 0.1 mol

    JP NO₂ = n NO₂ x L
    1.505 . 10²³ = n NO₂ x 6.02 . 10²³
    n NO₂ = 0.25 mol

    n CO₂ / v CO₂ = n NO₂ / v NO₂
    0.1 / 8 L = 0.25 / v NO₂
    v NO₂ = 20 L (E) ⇒ Jawab
    26. %O = 100% - 25,93% = 74.07%
    N : O = 25.93/14 : 74.04/16 = 1.85 : 4.6275 = 2 : 5
    Rumus kimia : N₂O₅ (E) ⇒ Jawab
    27. Ar L + 3 x Ar O + 3 x Ar H = 78
    Ar L + 3 x 16 + 3 x 1 = 78
    Ar L = 27 g/mol (C) ⇒ Jawab
    28. n CO(NH₂)₂ = massa CO(NH₂)₂ / MR CO(NH₂)₂
    3 = massa CO(NH₂)₂ / 60
    massa CO(NH₂)₂ = 180 gram (D) ⇒ Jawab