50 ml 0,1 M larutan NH3 dicampur dg 100 ml 0,5 M larutan NH4Cl Kb.10^-5 hitunglah pH campuran
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Pertanyaan
50 ml 0,1 M larutan NH3 dicampur dg 100 ml 0,5 M larutan NH4Cl Kb.10^-5 hitunglah pH campuran
1 Jawaban
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1. Jawaban wina0603
Mol basa = 0,1M . 0.05liter = 5*10^-3 mol
Mol garam = 0,1 liter . 0.5M = 0,05 mol
OH-] = kb . Mol basa / valensi . Mol garam
= 10^-5 . (5*10^-3) / 1 . 0,05
= 5* 10^-8 / 5 * 10^-2
= 10^-6
Poh = 6
Ph = 14-6 =8