fungsi f(x) = -4 sin 3 (x-phi/2) + 1 mempunyai nilai maksimum a dan nilai minimum b. Nilai (a-b) 2 =……………

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f(x) = - 4 sin 3(x - π/2) + 1

untulk -1 ≤ sin 3(x-π/2)  ≤ 1

tertinggi sin (ax  +b) = 1
terendah sin (ax + b ) = - 1

f(x) = - 4 (1) + 1 = - 4  + 1 = - 3
f(x) = - 4(-1) +1  = 4  + 1 =  5
Maksimum  a=  5
minimum b = - 3

(a- b)²  = (5 - (-3))²= (8)² = 64