Yang tau tolong jawab ya makasih

∫ x² ( x³+1)³ dx
maka
U = x³ + 1
U' = 3x³⁻¹
    = 3x²
dx = du/u'
dx = 1/3x²

∫ x² (x³ +1)³ dx
= x² U³ 1/3x² + C
= x² . 1/3x²  U³ + C
= 1/3 U³ + C
= 1/3 /(3+1) U³⁺¹ + C
= 1/3 / 4 U⁴
= 1/3 x 1/4 U⁴ + c
= 1/12 ( x³+1)⁴ c