Matematika

Pertanyaan

Diketahui tan x = p, maka cos 2x =

1 Jawaban

  • tan x = p = p/1 = de/sa => mi = √(p^2 + 1^2) = √(p^2 + 1)
    sin x = de/mi = p/√(p^2 + 1)
    cos x = sa/mi = 1/√(p^2 + 1)

    Cos 2x = (cos x)^2 - (sin x)^2
    = 1/(p^2 + 1) - p^2/(p^2 + 1)
    = (1 - p^2)/(p^2 + 1)

    = (1 - p^2)/(1 + p^2)

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