tentukan fungsi invers dari fungsi berikut : f(x) = 2x + 1 / x - 3 , x ≠ 3

f(x) = (2x + 1) / (x - 3)
Jika f(x) = (ax + b) / (cx + d)
f^(-1)(x) = ( -dx + b) / (cx - a)
a = 2 , b = 1 , c = 1 , d = -3
Maka f^(-1)(x)
= (3x + 1) / (x - 2)

Bisa jg
y = (2x + 1) / (x - 3)
y(x - 3) = (2x + 1)
xy - 3y = 2x + 1
xy - 2x = 3y + 1
x(y - 2) = 3y + 1
x = (3y + 1) / (y - 2)
f^(-1)(x) = (3x + 1) / (x - 2)