jika f(x) = 3x^2 -2ax +7 dan f aksen (1) =0 maka f aksen (2) adalah

Bab Turunan

Turunkan dulu f(x)
f'(x) = 2.3x^(2 - 1) - 1.2ax^(1 - 1) + 0.7x^(0 - 1)
f'(x) = 6x - 2a

Cari nilai a
f'(1) = 6(1) - 2a
0 = 6 - 2a
2a = 6
a = 3

f'(2) = 6(2) - 2(3)
f'(2) = 12 - 6
f'(3) = 6

f(x) = 3x² - 2ax + 7
f'(x) = 6x - 2a + 0
f'(x) = 6x - 2a

Masukkan nilai f'(1) = 0 ↓↓↓
f'(x) = 6x - 2a
0 = 6(1) - 2a
0 = 6 - 2a
2a = 6
a = 6/2
a = 3

Maka f'(2) adalah ↓↓↓
f'(x) = 6x - 2a
f'(2) = 6(2) - 2(3)
f'(2) = 12 - 6
f'(2) = 6