jika fx = x pangkat 5 ditambah mx pangkat 4 dikurang 2 x pangkat 3 ditambah x ditambah 1 dan f( 2) = 3 maka nilai f(-2)adalah

Langsung aja y

f(x) = x^5 + mx⁴ - 2x³ + x + 1

f(2) = (2)^5 + m(2)⁴ - 2(2)³ + 2 + 1
3 = 32 + 16m - 16 + 3
16m = 3 - 32 + 16 - 3
16m = -16
m = -1

f(x) = x^5 +(-1)x⁴ - 2x³ + x + 1
f(x) = x^5 - x⁴ - 2x³ + x + 1

maka
f(-2) = (-2)^5 - (-2)⁴ - 2(-2)³ - 2 + 1
f(-2) = -32 - 16 + 16 - 1
f(-2) = -32 - 1
f(-2) = -33

semoga berguna +_+