Matematika

Pertanyaan

Tentukan f'(x) jika fungsinya f(x)=2 √x^5-3x²+x

1 Jawaban

  • f(x) = 2√(x^5 - 3x² + x)
    f(x) = 2(x^5 - 3x² + x)^½
    f'(x) = 2(½)(5x⁴ - 6x + 1)(x^5-3x²+x)^(½-1)
    f'(x) = (5x⁴-6x+1)(x^5-3x²+x)^-½
    f'(x) = (5x⁴-6x+1)/(x^5-3x²+x)^½
    f'(x) = (5x⁴-6x+1) / √(x^5-3x²+x)

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