Matematika

Pertanyaan

bagaimana cara kerjanya?
bagaimana cara kerjanya?

2 Jawaban

  • fog(x) = 3x² - 16x + 12
    f(2 - x) = 3x² - 16x + 12
    f(-1) = ...
    2 - x = -1
    2 + 1 = x
    x = 3
    f(3) = 3(3)² - 16(3) + 12 = 27 - 48 + 12 = -9
  • (f o g)(x) = 3x^2 - 16x + 12
    f(g(x)) = 3x^2 - 16x + 12
    f(2 - x) = 3x^2 - 16x + 12
    Misal a = 2 - x => x = 2 - a
    f(a) = 3(2 - a)^2 - 16(2 - a) + 12
    f(-1) = 3(2 - (-1))^2 - 16(2 - (-1)) + 12
    = 3(3)^2 - 16(3) + 12
    = 27 - 48 + 12
    = -9