Matematika

Pertanyaan

lim mendekati 0 sin 2x cot 3x

2 Jawaban

  • Bab Limit
    Matematika SMA Kelas XI

    Lim (sin 2x . cot 3x)
    x→0
    = lim (sin 2x . Cos 3x/sin 3x)
    ...x→0
    = lim (sin 2x/sin 3x . Cos (3 . 0))
    ...x→0
    = 2/3
  • identitas limit
    lim sin ax/tan bx = a/b
    x→0

    lim sin2x cot3x
    x→0
    = lim sin2x × 1/tan3x
    x→0
    = lim sin2x / tan3x
    x→0
    = 2/3

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