Nyatakan titik A(3,-3akar3) kedalam koordinat kutub

Koordinat kutub

A(x,y)= (3 , -3√3)

r = √(x²+y²)
r = 6

α = tan¹ (y/x) --> α = tan⁻¹ (-√3)
tan α = - √3 --> tan α = - tan 60
x > 0 , y<  0 ,, α = IV
- tan 60 = tan (360-60)= tan 300
α = 300

Kordinat kutub =r, α = {6, 300°}