no.39 kak please......

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Diketahui :
ggl, ε = 12 Volt
R1 = 6 ohm
R2 = 12 ohm
R3 = 9 ohm

Ketiganya dipasang paralel maka Hambatan penggantinya adalah 
1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/6 + 1/12 + 1/9

1/R = 6/36 + 3/36 + 4/36

1/R = 13/36

R = 36/13 ohm 

Step 2
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maka arus yg mengalir adalah 

I = ε / R

I = 12 / (36/13)

I = 12 x 13/36

I = 13/3

I = 4,33 Ampere

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FZA
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