sec α tan² α + sec a = a. sec α b. sec² α c. sec³ α d. cosec α e. cosec² α
Matematika
SMelani30
Pertanyaan
sec α tan² α + sec a =
a. sec α
b. sec² α
c. sec³ α
d. cosec α
e. cosec² α
a. sec α
b. sec² α
c. sec³ α
d. cosec α
e. cosec² α
1 Jawaban
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1. Jawaban virgeenanuvi
sec a tan² a + sec a = ?
[tex] \frac{1}{cos a} \frac{ sin^{2}a }{ cos^{2}a } + \frac{1}{cos} \\ = \frac{1}{cos a} \frac{ sin^{2}a }{ cos^{2}a } + \frac{1}{cos} \frac{ cos^{2}a }{ cos^{2}a } \\ = \frac{ sin^{2}a + cos^{2}a }{ cos^{3}a } \\ = \frac{1}{ cos^{3}a } \\ = sec^{3}a [/tex]
Jawabannya C. sec³ a
ingat:
sin² a + cos² a = 1
sec = 1/cos a
cosec = 1/sin a