Sistem persamaan 2 per x tamabh 3 perx =5 dan 3 perx dikurang 4per x =16 nilai x0 y0?

mungkin per x dan per y kali
2/x + 3/y = 5
3/x - 4/y = 16
misalkan 1/x = p
1/y = q
2p + 3q = 5 |×3| ---> 6p + 9q = 15
3p - 4q = 16 |×2| ---> 6p - 8q = 32
eliminasi -----------> ------------------- _
17q = -17
q = -1
2p + 3(-1) = 5
2p - 3 = 5
2p = 5 + 3
p = 8/2 = 4

1/x = p
1/x = 4
x = 1/4
1/y = q
1/y = -1
y = -1
x + y = 1/4 + (-1) = 1/4 - 1 = 1/4 - 4/4 = -3/4