Matematika

Pertanyaan

[tex] \int\limits( 2 x^{2} +3)(3x-4) dx =[/tex]

1 Jawaban

  • Bab Integral

    [tex] \int {(2x^2+3)(3x - 4)} \, dx [/tex]
    = [tex] \int {6x^3 -8x^2 +9x-12} \, dx [/tex]
    = [tex] \frac{6}{3+1} x^{3+1}- \frac{8}{2+1}x^{2+1} + \frac{9}{1+1}x^{1+1} -\frac{12}{0+1} x^{0+1}[/tex]
    = [tex] \frac{6}{4} x^{4}- \frac{8}{3}x^{3} + \frac{9}{2}x^{2} -\frac{12}{1} x^{1}+C[/tex]
    = [tex] \frac{3}{2} x^{4}- \frac{8}{3}x^{3} + \frac{9}{2}x^{2} -{12} x+C[/tex]

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