Tentukan periode dari fungsi fungsi berikut! a.y=2sin (5x+1/6pi) +3. B.y=-tn 4x+2 C.y= 3cos (2x-50°)-2 Makasi

a) T = 360/5 = 72
b) T = 180/4 = 46
c) T = 360 / 2= 180

Rumus periode :
y = a sin (kx + b) + c => p = 2π/k
y = a cos (kx + b) + c => p = 2π/k
y = a tan (kx + b) + c => p = π/k

A) y = 2 sin (5x + π/6) + 3 => k = 5
p = 2π/5 = 72°

B) y = - Tan 4x + 2 => k = 4
p = π/4 = 45°

C) y = 3 cos (2x - 50°) - 2 => k = 2
p = 2π/2 = π = 180°