[tex] \int\limits(2x-5)(3x+1) dx =[/tex]

Bab Integral

[tex] \int {(2x - 5)(3x + 1)} \, dx [/tex]
= [tex] \int {6x^2+2x- 15x-5} \, dx [/tex]
= [tex] \int {6x^2-13x-5} \, dx [/tex]
= [tex] \frac{6}{2+1} x^{2+1} - \frac{13}{1+1} x^{1+1} - \frac{5}{0+1} x^{0+1}[/tex]
= [tex]2x^3 - \frac{13}{2} x^{2} - 5 x + C[/tex]