Jika f(x) = sin^5 (2x - 3) maka f'(x) =

f'(x) = 5 sin^4 (2x-3) * 2
f'(x) = 10 sin^4 (2x-3)

cara panjang :
U= (2x-3)
U'= 2
F= sin^5 U
F'= 5 sin ^5-1 U . 2
   = 10 sin^5-1 (2x-3)