haii guys , tolongin jawab yah yang nomer 35&38 aja.. please answer + caaranya , thx u❤

35][
s = 15 cm
F = 12 cm
M = ?

Penyelesaian:
1) Cari jarak bayangan ke cermin dulu
1/s' = 1/f - 1/s
1/s' = 1/12 - 1/15
1/s' = 5/60 - 4/60
1/s' = 1/60
s' = 60 cm
2) Cari M,
M = |s'/s|
M = |60/15|
M = 4 <- jwb

38][
s = 20 - 5 = 15 cm
f = 20 cm
M = ?
Sifat bayangan = ?

Penyelesaian:
1) Cari s'-nya
1/s' = 1/f - 1/s
1/s' = 1/20 - 1/15
1/s' = 3/60 - 4/60
1/s' = - 1/60
s' = -60 cm

M = |s'/s|
M = |-60/15|
M = 4 <- jwb

Benda di R1, sifat bayangan:
- Maya,
- Tegak,
- Diperbesar,
- Bayangan di R. 4