Jawab no 6 7 dan 11'. Minta bantuannya kawan

6) BC^2 = AB^2 + AC^2
BC^2 = (√3 + 2)^2 + (√6)^2
BC^2 = 3 + 4√3 + 4 + 6
BC^2 = 13 + 4√3
BC^2 = 13 + 2.2√3
BC^2 = 13 + 2√12
BC = √(13 + 2√12)
BC = √((12 + 1) + 2√(12.1))
BC = √12 + √1
BC = (2√3 + 1) cm

7) luas = 7 - √2
p . l = 7 - √2
p . (√2 - 1) = 7 - √2
p = (7 - √2)/(√2 - 1) . (√2 + 1)/(√2 + 1)
p = (7√2 + 7 - 2 - √2) / (2 - 1)
p = (5 + 6√2) / 1
p = 6√2 + 5
p = A√B + C
A = 6, B = 2, C = 5

11) (√6 + √3 + √2)/(√6 + √3 - √2)
= ((√6 + √3) + √2)/((√6 + √3) - √2) . ((√6 + √3) + √2)/((√6 + √3) + √2)
= (6 + √18 + √12 + √18 + 3 + √6 + √12 + √6 + 2) / ((√6 + √3)^2 - 2)
= (11 + 2√18 + 2√12 + 2√6) / ((6 + 2√18 + 3) - 2)
= (11 + 2.3√2 + 2.2√3 + 2√6) / (7 + 2.3√2)
= (11 + 6√2 + 4√3 + 2√6) / (7 + 6√2) . (7 - 6√2)/(7 - 6√2)
= (77 - 66√2 + 42√2 - 72 + 28√3 - 24√6 + 14√6 - 12√12) / (49 - 72)
= (5 - 24√2 + 28√3 - 10√6 - 12 . 2√3) / -23
= (5 - 24√2 + 4√3 - 10√6) / -23

= -1/23 (5 - 24√2 + 4√3 - 10√6)

= 1/23 (-5 + 24√2 - 4√3 + 10√6)