lim x mendekati 2. 4-x^2/3-akar x^2+5

limit (x -> 2)  (4 - x²) / (3 - √(x²+5))
lim(x->2)   (4 - x²)(3 + √(x² +5)) /(3 - √(x²+5))(3 + √(x²+5)
lim(x->2) (4 - x²)(3 +√(x²+5) / (9 - x² - 5)
lim (x->2)  (4 - x²) (3 + √(x²+5))/ (4 - x²)
lim (x->2)  3+ √(x² +5)
x = 2
= 3 + √(4+5)
= 3 + 3
= 6

jawaban ada di lampiran :)