tolong nomor 14,15 yaaa
Matematika
Nikitalourdey16
Pertanyaan
tolong nomor 14,15 yaaa
1 Jawaban
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1. Jawaban hoji
15) tan 30° = CD/2√6
1/√3 = CD/2√6
CD = (1/√3) × (2√6)
CD = 2√6 / √3
sin 45° = (2√6 / √3)/BC
√2/2 = (2√6 / √3)/BC
BC = (2√6 / √3)/(√2/2)
BC = 4√6/√6
BC = 4 cm ........................................C