tolong selesaikan no 3 dan 5

3. [(2^3 y^6 z^7) / (2^2 y^4 z^4)]^3 = [2^(3-2) y^(6-4) z^(7-4)]^3
= [2^1 y^2 z^3]^3
= 2^3 y^6 z^9

5. 2q + 6 - [-2 (3q + 2)] = 2q + 6 + 2 (3q + 2)
= 2q + 6 + 6q + 4
= 8q + 10