lim mendekati 0 sin 2x + cos x sin 2x/tan x + 3 tan x sec x
Matematika
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Pertanyaan
lim mendekati 0 sin 2x + cos x sin 2x/tan x + 3 tan x sec x
1 Jawaban
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1. Jawaban DB45
limit bentuk 0/0
lim(x->0) sin 2x ( 1 + cos x) / ( tan x)(1 + sec x)
lim(x->0) [ sin 2x / tan x ] + lim(x->0) (1 + cos x) / ( 1 + sec x)
lim(x->0) [ sin 2x / tan x] + lim(x->0) cos x
= 2x/x + cos 0
= 2 + 1
= 3